Math, asked by samirkarmacharya5, 10 hours ago

The odds against A speaking the truth are 4:6 while the odds in favour of B speaking the truth are 7:3, what is the probability that A and B contradicts each other in stating the same fact?

Answers

Answered by lennintennyson253
1

Answer:

A: 3:2 means that in 5 situation, A told

the True 3 times; as a fraction 3/5; and A

told the lies in (5-3)/5 = 2/5,

B:7:3 means that 7 +3 = 10 situation,

B told the True; in 7 out of 10. As a

fraction 7/10 and B told lies in 3 out of 10

situations. As a fraction 3/10

Both contradict each other when A told

the True and B lied. As fractions

3/5 x 3/10 = 9/ 50 = 18 %

Or A lied and B told the True. As

fractions: 2/5 x 7/10 = 14/50 = 28%

Both Agree. when A and B told the True;

3/5 x 7/10 = 21/50 or 42%

Both disagree when both lied; 2/5 x 3/5 =

6/50 = 12 %

Probability of Agreement : 42 + 12 = 54 %

Probability of Contradiction : 18 + 28 = 46

%:

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