The odds in favour of an event A are 2:5. The odds against another independent event B are 5:1. What is the probability that one of the events will happen?
19/25
1/21
1/6
17/42
Answers
Answer:
Answer
let the two events be E
1
and E
2
Odd against favour of one are 5:2
⇒ odds in favour are 2:5
⇒ Probability of happenig of one =P(E
1
)=
7
2
⇒ probabiility of not happening one =P(
E
1
_
)=1−
7
2
=
7
5
odds in favour of two are 6:5
⇒P(E
2
)=
11
6
⇒P(
E
2
_
)=1−
11
6
=
11
5
Desired probabililty =P(E)=1−none of then happens
⇒P(E)=1−
7
5
×
11
5
=
77
52
Answer:
Here is your answer
Step-by-step explanation:
let the two events be E
1
and E
2
Odd against favour of one are 5:2
⇒ odds in favour are 2:5
⇒ Probability of happenig of one =P(E
1
)=
7
2
⇒ probabiility of not happening one =P(
E
1
_
)=1−
7
2
=
7
5
odds in favour of two are 6:5
⇒P(E
2
)=
11
6
⇒P(
E
2
_
)=1−
11
6
=
11
5
Desired probabililty =P(E)=1−none of then happens
⇒P(E)=1−
7
5
×
11
5
=
77
52