Math, asked by Majghar1203, 1 year ago

The odds in favour of winning a race by three boys are 1:3, 1:5, and 1:4 respectively. The probability of winning the race by only one of them is?
A) 7/20
B) 47/120
C) 17/60
D) 37/60

Answers

Answered by parisakura98pari

probabilty of winning of one guy = 1/4 + 1/5 + 1/6 = 37/60

doubts?? ask

parisakura98pari: do u want to know how ans came ?

Jaykatira: yes

parisakura98pari: its easy odds in favour means ratio of no of favourable outcomes to no of unfavourable one or say ratio of probability of occuring to probability of not occuring......

parisakura98pari: suppose now p(boy1) = a , p(boy2) = b and p(boy3) = c

parisakura98pari: A/Q : a/b+c = 1/3 ==== b+c/a = 3 and b/a+c = 1/4 ====a+c/b = 4 and c/a+b = 1/5 ====== a+b/c = 5

parisakura98pari: now a+b+c/a = 4 , a+b+c/b = 5 , a+b+c/c = 6

parisakura98pari: therefore a/a+b+c = 1/4 , b/a+b+c = 1/5 ,c/a+b+c = 1/6

parisakura98pari: so probability of winning of only one = 1/4 + 1/5 + 1/6

parisakura98pari: actually it should be n(boy1) = a , n(boy2) = b and n(boy3) = c no of favourable outcomes....got that?

Answered by Jaykatira

'Probability of winning of one boy is

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The odds in favour of winning a race by three boys are 1:3, 1:5, and 1:4 respectively. The probability of winning the race by only one of them is? A) 7/20 B) 47/120 C) 17/60 D) 37/60

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The odds in favour of winning a race by three boys are 1:3, 1:5, and 1:4 respectively. The probability of winning the race by only one of them is?
A) 7/20
B) 47/120
C) 17/60
D) 37/60