The odometer of a car reads 1800km at the start of the trip and 2400 km at hte end of the trip .if the trip took 10 hrs to complete.calculate the average speed n km/hr and m/sec.
Answers
Distance Covered = 2400-1800 = 600 km
Time = 10 Hrs
Speed = 600/10 = 60 km/hr
Distance in meter = 600*1000 = 600000
Time in Sec = 10* 3600 = 36000
Speed = 600000/36000 = 50/3 m/s
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Answer:
distance covered by the car
\begin{gathered}s = 2400 - 2000 \: km \: = 400 \: km \: \\ time \: elapsed \: t \: = 8 \: h \: \\ average \: speed \: of \: car \: is \: \\ v \: av \: = \frac{s}{t} \: = \frac{400}{8h} \: km \: \\ 50 \: k m \: {h}^{ - 1} \\ 50 \: \frac{km}{h} \times \frac{1000}{1 \: km} \times \frac{1 \: km}{36 00 \: s } \\ = 13.9 \: {ms}^{ - 1} \: the \: average \: speed \ \\ of \: car \: is \: 50 \: km \: {h}^{ - 1} \: or \: 13.9 \: {ms}^{ - 1} \end{gathered}
s=2400−2000km=400km
timeelapsedt=8h
averagespeedofcaris
vav=
t
s
=
8h
400
km
50kmh
−1
50
h
km
×
1km
1000
×
3600s
1km
=13.9ms
−1
theaveragespeed
ofcaris50kmh
−1
or13.9ms
−1