Question

The odometer of a car reads 2000 km at the start of a trip and 2400 km at the end of the trip. If the trip took 8 h, calculate the average speed of the car in
$km \: {h}^{ - 1} \: and \: {ms}^{ - 1} .$

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Answer 1

Answer:

Distance covered by the car,

s = 2400 km - 2000 km = 400 km

Time elapsed, t = 8 h

Average speed of the car is,

$v_{av} = \frac{s}{t} = \frac{400 \: km}{8 \: h}$

$= 50 \: km \: {h}^{ - 1}$

$= 50 \frac{k}{m} \times \frac{1000m}{1km} \times \frac{1h}{3600s}$

$= 13.9 \: {ms}^{ - 1}$

$\therefore \: the \: average \: speed \: of \: the \: car \: is \: 50km \: {h}^{ - 1} or \: 13.9 {ms}^{ - 1} .$