Math, asked by yashikapathak08, 6 months ago

The odometer of a car-reads the following distances at the given instants. The ratio of average speed of the
car in the first and the second intervals is
Odometer reading
9:45 AM
4404 km
10:16 AM
4449 kn
10 30 AM
4469 km
(2) 8 : 9
(1)
ndations
(3)
9.2
(4): 2:1​

Answers

Answered by chinmaymewari3
7

Answer:

9:8

Step-by-step explanation:

Average Speed of 1^{st} interval = \frac{45 km}{30 min}

                                                   = \frac{45*60}{30} km/h

                                                   = 90 km/h

Average Speed of 2^{nd} interval = \frac{20km}{15min}

                                                   =  \frac{20*60}{15}km/h

                                                    = 80 km/h

Hence, Ratio =  Average Speed of 1^{st} interval / Average Speed of 2^{nd} interval

                       = \frac{90}{80}

                       = \frac{9}{8}

                       = 9:8

HOPE YOU UNDERSTOOD !!

MARK IT AS THE BRAINLIEST !!!

Similar questions