The of angle of elevation from top of tower from point ground which is 15m away from foot of tower is 30 degree.find the height of tower
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Step-by-step explanation:
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Step-by-step explanation:
In ∆ ABC,
tan ∅ = Perpendicular/Height
tan 30° = AB/BC
1/√3 = AB/30
30/√3 = AB
AB = 30/√3
Now, Multiplying numerator and denominator by 3 we get:
AB = 30/√3 × √3/√3
AB = 30√3/3
AB = 10√3
Therefore, the height of the tower is 10√3.
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