The % of C = 40, H = 6.6 and rest is oxygen. If the V.D of the compound is 90, what is the molecular formula?(C=12, H =1, O=16)
Answers
Answer:
now see
Explanation:
Let amount of organic = 100 gm
amount of carbon = 54.55 g
amount of hydrogen = 9.09 g
Amount of oxygen = 36.26 g
number of mole of carbon =
12
34.55
=4.54583
number of mole of hydrogen =
1.018
9.09
=9
number of mole of oxygen =
16
36.26
=2.26
4.54833:9:2.26
2:4:1
organic compounds Empirical formula
=C
2
H
4
O
Molecular weight = 24+4+16=44
(for empirical)
Molecular weight = 2× vapour density
=2×44=88 g
To molecular formula be = C
4
H
8
O
2
Answer:
Answer
Let amount of organic = 100 gm
amount of carbon = 54.55 g
amount of hydrogen = 9.09 g
Amount of oxygen = 36.26 g
number of mole of carbon =
12
34.55
=4.54583
number of mole of hydrogen =
1.018
9.09
=9
number of mole of oxygen =
16
36.26
=2.26
4.54833:9:2.26
2:4:1
organic compounds Empirical formula
=C
2
H
4
O
Molecular weight = 24+4+16=44
(for empirical)
Molecular weight = 2× vapour density
=2×44=88 g
To molecular formula be = C
4
H
8
O
2