Question

the
of P ( x ) = x²-x²+x+1, then
then find
value of P(1) + P(-)
2​

Answer 1

Answer:

1. hii. jghiolnvgfddjkppkjhu

Answer 2

• $\huge{\underline{\underline{\boxed{\sf{\red{Answer࿐}}}}}}$Given the polynomial p(x)=x
• 3
• −x
• 2
• +x+1
• \text{we have to find the value of }\frac{1}{2}(p(-1)+p(1))we have to find the value of
• 2
• 1
• (p(−1)+p(1))
• p(x)=x^3-x^2+x+1p(x)=x
• 3
• −x
• 2
• +x+1
• Put x=-1 and x=1
• p(-1)=(-1)^3-(-1)^2+(-1)+1=-1-1-1+1=-2p(−1)=(−1)
• 3
• −(−1)
• 2
• +(−1)+1=−1−1−1+1=−2
• p(1)=(1)^3-(1)^2+(1)+1=1-1+1+1=2p(1)=(1)
• 3
• −(1)
• 2
• +(1)+1=1−1+1+1=2
• \frac{1}{2}(p(-1)+p(1))
• 2
• 1
• (p(−1)+p(1))
• =\frac{1}{2}(-2+2)=0=
• 2
• 1
• (−2+2)=0
• \text{Hence, the value is }\frac{1}{2}(p(-1)+p(1))\text{ is 0.}Hence, the value is
• 2
• 1
• (p(−1)+p(1)) is 0.