the of the length and the breadth of a rectangular field are in the ratio 9 ratio 5 if the area of field is 14580 square metre,find the cost of surrounding the field with a fence at the rate rupees 3. 25 per metre
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length=9x
breadth=5x
area=lxb
14580=9x ×5x
45x^2=14580
x^2=324
x=18 metre
length=9×18=167
breadth=5×18=90
perimeter=2(l+b)
2(167+90)
2(257)
=514 metre
cost=3.25
514×3.25
rupees 1670.5
breadth=5x
area=lxb
14580=9x ×5x
45x^2=14580
x^2=324
x=18 metre
length=9×18=167
breadth=5×18=90
perimeter=2(l+b)
2(167+90)
2(257)
=514 metre
cost=3.25
514×3.25
rupees 1670.5
brainliest007:
brilliant answer by me
Answered by
0
Let the length of rectangle be 9x and its breadth be 5x
So,
Area = l × b
⇒ 14580 = 9x × 5x
45x2 = 14580
x2 = 14580/45 = 324
x = √324
x = 18
Hence,
Length = 9 × 18 = 162 m and Breadth = 5 × 18 = 90 m
Now, Perimeter = 2(l + b)
= 2 (162 + 90) = 2(252)
= 504 m.
Therefore, cost for fencing the surrounding 504 m at the rate of ₹3.25 per metre = ₹(504 × 3.25) = ₹1638
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