Question

The (OH) in 100.0 mL of 0.015 M HCl(aq.)
solution is
a) 5 x 10-12 M
b) 3 x 10-10 M
c) 6.7 x 10-14M
d) 2.0 x 10-9M

Pls answer!!

Answer 1

Answer:

we know that..

HCl. = H. + Cl

0.015. 0.015. 0.015

Kw =. [H+] + [Oh-]

10^-14=. 0.015 [Oh-]

Oh- = 10^-14/0.015

= 6.7× 10^-14

so the correct ans is option( c)

hope it will help you........