the one angle of a triangle is 3 times the other and the third angles is half of the sum of the two angles find the angles
Answers
Answered by
1
Let the first angle be a
Second angle = 3a
Third angle = ( a + 3a)/2 = 4a/2 = 2a
By angle sum property of triangle,
a + 3a + 2a = 180
=> 6a = 180
=> a = 30
First angle = 30°
Second angle = 90°
Third angle = 60°
Second angle = 3a
Third angle = ( a + 3a)/2 = 4a/2 = 2a
By angle sum property of triangle,
a + 3a + 2a = 180
=> 6a = 180
=> a = 30
First angle = 30°
Second angle = 90°
Third angle = 60°
praveenyadav51:
thanks you brother
Answered by
0
let the first angle be x°. then the , second angle be 3x° and the third angle = {1/2 × (x+3x)}° = (1/2×4x)°= 2x°.
we know that the sum of all the angles of a triangle is 180°.
Therefore, x + 3x + 2x = 180
6x = 180
x = 180/6
x = 30 .
Therefore, first angle = 30° , second angle = (3×30)°= 90° and third angle = (2×30)° = 60°.
we know that the sum of all the angles of a triangle is 180°.
Therefore, x + 3x + 2x = 180
6x = 180
x = 180/6
x = 30 .
Therefore, first angle = 30° , second angle = (3×30)°= 90° and third angle = (2×30)° = 60°.
Similar questions