Question

The one digit in a 2digit number is 3 times the digits at the ones places .If the sum of the two digits is8 find the number​

Answer 1

Answer:

ANSWER

Let the digit in units place be x.

Then, digit in ten's place =3x

So, original number =10(3x)+x=31x

On interchanging the digits, new number =10x+3x=13x

According to the given condition,

31x+13x=88

⇒44x=88

⇒x=2

So, the original number is 31x or 31×2=62.

On the other hand, if we consider the digit in ten's place as x, then the digit in unit's place will be 3x.

So, the resulting number we get is 26.

Here, both answers are correct, as 26+62=88.

Step-by-step explanation:

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Answer 2

Answer:

62

Step-by-step explanation:

let the unit digit be x then according to question tenth digit is 3x.

also as the tens digit is 3x the number formed will be 30 X + unit digit which is x. So the number form will be in the form of 31 x.

it is given that the sum of the two digits is 8

it means 3 X + x = 8

4 x = 8

X equal to 2

now the number is 31 x

which means 31 x

So, the number is 62

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