Question

The one electron species having ionisation energy of 54.4ev is

Answer 1

Explanation:

The one electron species having ionization energy of 54.4 EV is. The one electron species having ionization energy of 54.4 EV is .

Answer 2

The one electron species having ionisation energy of 54.4ev is $He^+$

Explanation:

Ionization energy to ionize the electron from one electron species will equal to the difference between energy of electron at infinity from the energy of electron at n = 1 energy level.

$I.E=E_{\infty }-E_1$

$54.4eV=0-E_1$

$E_1=-54.4eV$

$E_n=-13.6\times \frac{Z^2}{n^2}eV$

where,

$E_n$ = energy of nth orbit  

n = number of orbit  = 1

Z = atomic number  = ?

Putting in the values we get:

$-54.4=-13.6\times \frac{Z^2}{1^2}eV$

${Z^2}=4$

$Z=2$

The atomic number of helium is 2. Thus the one electron species having ionization energy of 54.4ev is $He^+$

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