the one root of quadriatic equation is on (3x - 6) ( x -3 ) =0 is 3 then other is
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Let a,b o be three distince positive real numbers. Then the number of real roots of ax2 +2b∣x∣+c=0 is (−1) 6.4 (B) D+ ...
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x= 3 x = 2
Step-by-step explanation:
x-3= 0
x = 3
3x-6=0
x= 6/3
x=2
the roots are 3 2
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