The one’s digit in a two-digit number is 7 greater than the ten's digit. If we interchange the digits in the number, we obtain a new number that, when added to the original number, results in the sum 99. Find this number
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Step-by-step explanation:
so let the two digit number be 10x+y
wherein the digit at tens place is x and that of units is y
so according to first situation
y=x+7 (1)
according to second case
10y+x+10x+y=99
ie 11x+11y=9
so x+y=9 (2)
substitute value of y in (2)
from (1) we get
2x+7=9
ie 2x=2
ie x=1
so substitute now value of x in any of 2 equations you get
y=8
hence our two digit was:-10x+y=(10×1)+8
=10+8
=18
hence required two digit number is 18
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