The one's digit number is double the digit in ten place. If the sum of digit is 9, find the number.
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Let x be the ten's digit.
One's digit = 2x
Required number = x × 10 + 2x
Also,
x + 2x = 9
x = 9 / 3
x = 3
Therefore,
Required number = 3 × 10 + 2 × 3
= 30 + 6
= 36
Hence the required number is 36.
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