Question

the one who gives the answer for these would be marked as brainiest

Answer 1

Answer:

(1) Let us take the class mark in each case and create a table containing only  the class mark and the frequency .

class mark=(upper class limit+lower class limit)/2

height of the plant(x)         frequency(f)             fx

5                                                   1                           5

15                                                 4                           60

25                                                 7                           175

35                                                 2                            70

45                                                 3                              135

55                                                 3                              165

Sum of frequency=20

sum of fx=610

mean=610/20=30.5 cm

(3)

    (a) you have already marked the answer to this question on the graph with the help of a red cross.

   (b)After each year the value of the car increases by 2000 pounds

   (c)The 3 1/2 year old mark is the darkened line between 3 and 4

       The value of the car will be 3000 pounds.

(2) The modal class interval will be 24<a<26, as this class has the maximum frequency ,i.e., 8

     (b)age               class mark(x)                 frequency(f)          fx

          18<a<20          19                                      3                        57

          20<a<22         21                                      2                         42

           22<a<24        23                                      7                     161

            24<a<26        25                                     8                        200

We are not including the 26<a class because it has 0 frequency

Sum of f=20

sum of fx=460

mean=460/20=23

PLEASE MARK AS BRAINLIEST.