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Answer:given =) x = 3+√8
To find= x² + 1/x²
= (3+√8)²+1/(3+√8)²
= {(3)² + (√8)² + 2(3)(√8)} +1/{(3)² + (√8)² + 2(3)(√8)}
= {9+8+6√8}+1/{9+8+6√8}
= 23√8+1/23√8
= 23√8/1+1/23√8[LCM OF DENOMINATOR IS 23√8]
= (23√8*23√8)+1/23√8[simplifying]
= 23*23*8+1/23√8
= 4233/23√8 [multiplying by √8/√8]
= 4233√8/23
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