Question

The one who will give Answer is "d.umbo"

$\frac{ {3-2√2}^{2} }{ {3}^{2} - {2√2}^{2} } = ?$​

Answer 1

Answer :

$\frac{(3 - 2 \sqrt{2} ) {}^{2} }{(3) {}^{2} - (2 \sqrt{2}) {}^{2} } \\ \\ \frac{(3) {}^{2} +( 2 \sqrt{2}){}^{2} - 2 \times3 \times 2 \sqrt{2} }{9 - 8} \\ \\ \frac{9 + 8 - 12 \sqrt{2} }{1} \\ \\ \boxed{ \bf 17 - 12 \sqrt{2}}$

Thanks!