Question

the one who will solve it correctly will be appreciated

Find 'k' if (x-1) is a factor of 2x²+kx+√2

Answer 1

Hey

Here is your answer,

(x-1) is a factor of 2x²+kx+√2

X - 1 = 0
X = 1

Substitute the value of x in equation,

2 ( 1 )^2 + k (1) + √2 = 0
2 x 1 + k + √2 = 0
2 + k + √2 = 0
k = -2 - √2
k = 2+√2

Hope it helps you!

Answer 2

x-1 = 0
x = 1

2 × (1)² +k × 1 + √2 = 0

2+k +√2 = 9

k = (-2-√2)