Question

The one with the best answer , will receive the brain list answer

Answer 1

Step-by-step explanation:

area of shaded part= area of ∆ABC -area of ∆ADE

since both triangles are right angled ,we can use the formulae,

area

$\frac{base \times height}{2}$

• 1/2 × 20 ×21
• 210 - area of ∆ABC
• 1/2 × 10×10.5
• 52.5- area of ∆ADE

shaded area= 210-52.5

=157.5m²

Answer 2

Step-by-step explanation:

$\huge \mathcal \red{A}\huge \mathcal \green{n} \huge \mathcal \orange{s}\huge \mathcal \blue{w}\huge \mathcal{e}\huge \mathcal \green{r - }$

$\fbox{Area \: of \: \: a \: Δ = \frac{1}{2} \times base \times height}$

$Area \: of \: \: a \: ΔABC = \frac{1}{2} \times base \times height \\ \\ \frac{1}{2} \times 20 \times 21 \\ \\ 10 \times 21 \\ \\ = 210 \: cm {}^{2}$

$Area of ΔADE = \frac{1}{2} \times base \times height \\ \\ \frac{1}{2} \times 10 \times 10.5 \\ \\ 5 \times 10.5 \\ \\ 52.5 \: cm {}^{2}$

Area of Shaded Region = Area of ΔABC - Area of ΔADE

$(210 - 52.5 ) {cm}^{2} \\ \\ 157.5 \: {cm}^{2}$