the one with the largest delta0 value is
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Answer:
Correct option is
B
[Cr(H
2
O)
6
]
+3
The value of △
o
increases with increase in oxidation state of central metal, since maximum charges causes more left and hence orbital contracts lead to more CFSE(△
o
)
cr
3+
→t
2g
3
eg
o
→CFSE=∣−6/5∣△
o
Mn
3+
→d
4
→t
2
g
3
eg
1
→CFSE=−6/5△
o
+3/5△
o
=∣−3/5∣△
o
∴△
o
=cr
3+
>Mn
3+
Explanation:
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