Question

the ones and tens digit number after reversing the digit it becomes 110 and the difference between the two numbers is 6 find the number


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Answer 1

Answer:

We can let the digits of the number be a and b.

First number:

10a+b

Second number (first number with digits reversed):

10b+a

The two of them sum to 110:

(10a+b)+(10b+a)=110

Difference of the digits is 6:

b=a+6

Plug everything in and solve:

(10a+(a+6))+(10(a+6)+a)=110

11a+11a+66=110

22a=44

a=2

b=a+6=2+6=8

Our numbers are 28 and 82. Quick check:

28+82=110✓

Answer 2

$\huge \bold \color{green}{Answer : }$

$\large \bold \color{green}{Step \: by \: step \: Explanation : }$

let once place digit=a tens=b

hence, no.=10b+a

reverse of no.=10a+b

diff of digits=a-b=6. or a=6+b

A.T.Q

10b+a+10a+b=110

11(a+b)=110

a+b=10

6+b+b=10

2b=4

b=2

a=6+2=8

hence no. is 28

and if b=6+1

no.=82

$\large \bold \color{green}{Answer : 82,28}$

$\large \bold \color{green}{Please \: mark \: as \: brainliest \: answer}$