The ones digit of a 2-digit number is twice the ten digit.When the number formed by reversing the digits is added to original number,the sum is 99.Find the original number.
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let the no be 10x+y
y=2x
reverse no
10y+x
10x+y+10y+x=99
11x+11y=99
11x+22x=99
33x=99
x=3
original no is 36
y=2x
reverse no
10y+x
10x+y+10y+x=99
11x+11y=99
11x+22x=99
33x=99
x=3
original no is 36
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