The ones digit of a 2-digit number is twice the tens digit. When the number
formed by reversing the digits is added to the original number, the sum is 99. Find
the original number.
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Answer:
Let the tens digits =x
so, ones digits = 2x
number= 10x+2x=12x
reverse number= 10{2x}+x=20x+x=21x
it is given that
12x+21x=99
or 33x= 99
so,x=3
original number =10x+2x
30+6
36 answer
Step-by-step explanation:
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