the ones digit of a 2 digit number is twice the tens digit when the no. is formed by reversing the digits is added to the original no. the sum is 99.find the original no.
Answers
let , from first condition
20x+y and 10y+2x
Adding them =22x+11y=99
Dividing by 11 to both sides
2x+y=9.........1
BUt there is no another equation hence
Put any value to satisfies codition
HEnce put x=6 and y=3 satisfies condition
So the number be 63 or 36
Let the ten's digit be y and one's digit be x.
Given, x = 2y. ------ (i)
The original number = 10x + y and the reverse number = 10y + x.
Given that number formed by reversing the digits is added to the original number the sum is 99.
⇒ 10y + x + 10x + y = 99
⇒ 10y + 2y + 10(2y) + y = 99
⇒ 10y + 2y + 20y + y = 99
⇒ 33y = 99
⇒ y = 3.
Substitute y = 3 in (i), we get
⇒ x = 2y
⇒ x = 6.
Therefore, Original number = 10y + x
= 10(3) + 6
= 36.
Hope it helps!