the ones digit of a 2-digits number is twice the tens digit. when the number formed by reversing the digit is added to the original number, the sum is 99. find the original number.
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6
Answer:
Step-by-step explanation:
Let the the digit at ones place to be 2x
And the digit at tens place to be x
Original number = 10(x) + 2x
= 12x
On reversing the number
New number = 10(2x) + x
= 21x
According to the questions
= Original number + new number = 99
= 21x +12x = 99
= 33x = 99
X = 3
Original number = 12*3
= 36
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15
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