Question

the ones digit of a 2digit number is twice the tens digit.when the number is formed by reversing the digits is added to the original number the sum is 99.find the original number.​

Answer 1

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let, the tens digit =x

so, ones digit =2x

.•. number= 10x+2x=12x

reverse number= 10×2x+x=20x+x=21x

it is given that,

12x+21x=99

or 33x=99

so, x=3

original number=10x+2x

=30+6

=36 answer.

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Answer 2

Answer:

Let the two digit number is xy

y is digit at unit's place

x is digit at ten's place

⇒ Number can be written as = 10x+y

According to the conditions : y=2x ___ (1)

and

(10x+y)+(10y+x)=99

⇒11x+11y=99

⇒x+y=9 (dividing by 11)

Now x+2x=9 (from (1))

⇒3x=9

⇒x=9/3=3

y=2x=6

⇒ Number is 36