Question

The ones digit of a 2digit number is twice the tens digit . When the number formed by reversing the digits is added to the original number,the sum is 99 . Find the original number.

Answer 1

Heya!!! Here is your answer

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Let the the digit at ones place to be 2x

And the digit at tens place to be x

Original number = 10(x) + 2x

= 12x

On reversing the number

New number = 10(2x) + x

= 21x

According to the questions

= Original number + new number = 99
= 21x +12x = 99

= 33x = 99

X = 3

Original number = 12*3
= 36

HOPE ITS HELP YOU

Answer 2

Hi there!

Let the one's digit be = y and ten's digit be = x

Given :-
y = 2x. ----(i)

♦ Original number = 10x + y
♦ Number when reversed = 10y + x

ATQ,

(10x + y) + (10y + x) = 99

10x + y + 10y + x = 99

11x + 11y = 99

x + y = 9. -----(ii)

Substituting y = 2x [ from eqn. (i) ] in Eqn. (ii) :-

x + 2x = 9

3x = 9

x = 9 / 3

x = 3

Substituting x = 3 in eqn. (i) :-

y = 2x

y = 2 × 3 = 6

Hence, The required answer is :-
The Original number is = 10x + y = 10(3) + 6 = 30 + 6 = 36

Hope it helps! :)