Question

the ones digit of a two digit number is twice the tens digit when the number formed by reversing the digit is added to original number the sum is99 find the original number

Answer 1

Here's The Answer ::


Let the tens digit no. be x

One's digit no. = 2x


=> Number
10 (x) + 2x
10x + 2x
12x

=> Reversing Number
10 (2x ) + x
20x + x
21x



=> According to Question

12x + 21x = 99
33x = 99
x = 99 /33
x = 3

=> Number
12x
12 × 3
36


Hope It Helps! !!