The ones digit of a two digit number of twice the tens digit . when the number obtaned by revercing is added to orginal number the sum is 99 .find the orginal number
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Let the tens digit =X
And ones = 2X
Number= 10x+2x=12x
Reverse number = 10x 2x+x =20x+ X =21x
It is given that 12x+ 21x =99
33x=99
So X=99/33=3
X=3
Original number= 10x+2x
=30+6
=36
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