Question

The ones digit of a two digit number of twice the tens digit . when the number obtaned by revercing is added to orginal number the sum is 99 .find the orginal number​

Answer 1

Answer:

Let the tens digit =X

And ones = 2X

Number= 10x+2x=12x

Reverse number = 10x 2x+x =20x+ X =21x

It is given that 12x+ 21x =99

33x=99

So X=99/33=3

X=3

Original number= 10x+2x

=30+6

=36