Physics, asked by aanshika755, 2 months ago

The open circuit terminal voltage of a battery is 12.6 V. When a resistance R=4 ohm is connected between the terminals of the battery, the terminal voltage of the battery is 10.4 V. What is the internal resistance of the battery?

Answers

Answered by pradeep08kumar84
1

Answer:

V1=12.6V

V2= 10.4V

R1=4 ohm

R2 =?

V=IR

\frac{v1}{v2} = \frac{r1}{r2}

v2

v1

=

r2

r1

\frac{12.6}{10.4} = \frac{4}{r2}

10.4

12.6

=

r2

4

\frac{r2}{4} = \frac{10.4}{12.6}

4

r2

=

12.6

10.4

R2=3.3ohm

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