The open circuit terminal voltage of a battery is 12.6 V. When a resistance R=4 ohm is connected between the terminals of the battery, the terminal voltage of the battery is 10.4 V. What is the internal resistance of the battery?
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Answer:
V1=12.6V
V2= 10.4V
R1=4 ohm
R2 =?
V=IR
\frac{v1}{v2} = \frac{r1}{r2}
v2
v1
=
r2
r1
\frac{12.6}{10.4} = \frac{4}{r2}
10.4
12.6
=
r2
4
\frac{r2}{4} = \frac{10.4}{12.6}
4
r2
=
12.6
10.4
R2=3.3ohm
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