The opposite angels of a parallelogram ABCD are given as A=(3x+20degree)and C(2x+70degree
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opposite angles of a parallelogram are equal, therefore;
angle A= angle C
3x+20=2x+70
3x-2x=70-20
x=50
therefore angle A=(3x50)+20= 170
angle C=(2x50)+70= 170
THEREFORE L.H.S = R.H.S , hence proved.
angle A= angle C
3x+20=2x+70
3x-2x=70-20
x=50
therefore angle A=(3x50)+20= 170
angle C=(2x50)+70= 170
THEREFORE L.H.S = R.H.S , hence proved.
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