Question

The opposite angles of a parallelelogram
(3x-2) and (x+48)o find the measure
of each angle of the parallelogram​

Answer 1

Step-by-step explanation:

Let four angles of given parallelogram taken in order be ∠A,∠B,∠Cand∠D respectively

Here opposite angles given ∠A=(3x−2)and∠C=(x+48)

We know that opposite angles of a parallelogram are equal

∴3x−2=x+48

2x=50

x=25

∴3x−2=73°

∠A=∠C=73°

Also we know that sum of two adjacent angles of a parallelogram is 180

∴∠A+∠B=180°

73°+∠B=180°

∠B=107°=∠D (Opposite angles are equal)

∴ All four angles of given parallelogram are 73°,107°,73°,107°

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