Math, asked by amrita9265, 1 year ago

The opposite angles of a parallelogram are (4y+5)°and (3y+15)°. Find all the angles of the parallelogram.​

Answers

Answered by raj108801
15

Answer:

4y + 5 = 3y  + 15 \\ 4y - 3y = 15 - 5 \\ y = 10

the angles are 45°

and (360° - 2×45°) / 2

= 270°/2 =135°

Answered by krishkhurana777
36

Answer:

Step-by-step explanation:

we know that in a parallelogram

opposite sides are equal

adjucent add up to 180

(4y+5)=(3y+15)

= 4y-3y=15-5

=y=10

so, (4y+5)=(40+5)=45

(3y+15)=(30+15)=45

therefore let adjucent sides be x

ATQ

45+x=180

=x=180-45

=x=135

the angles are

L1=45

L2=135

L3=45

L4=135

hope this helped

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