Math, asked by JOEL71, 1 year ago

The opposite angles of a parallelogram are (5x-4)° and (x+48)° find the measure of each angle

Answers

Answered by Anonymous
23
Hi friend,
ATQ (x+48)°=(5x-4)°
                4x=52
                  x=13
ATQ,
5x+4+∠A= 180°(adjacent angles)
69+∠A=180°
∠A= 111°
and ∠A=∠C=111°
and ∠B=180°-111
           =69° = ∠D
So ∠A=111°,∠B=69°,∠C=111°,∠D=69°
______________________________________________THANKS :) _____

JOEL71: I got 13,167,13,167
Answered by Anonymous
13
Hi friend !!

We know that opposite angles of a parallelogram are equal.

Hence ,
(5x-4)° = (x+48)°

5 x - x = 48 + 4

4 x = 52

x = 52/4

x = 13

Therefore , the angles are :

5x - 4
= 5 × 13- 4 = 61°


JOEL71: Therefore 180-13=167. is the answer. hence, 13,167,13,167... Thank you!
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