The opposite angles of a parallelogram are (5x-4)° and (x+48)° find the measure of each angle
Answers
Answered by
23
Hi friend,
ATQ (x+48)°=(5x-4)°
4x=52
x=13
ATQ,
5x+4+∠A= 180°(adjacent angles)
69+∠A=180°
∠A= 111°
and ∠A=∠C=111°
and ∠B=180°-111
=69° = ∠D
So ∠A=111°,∠B=69°,∠C=111°,∠D=69°
______________________________________________THANKS :) _____
ATQ (x+48)°=(5x-4)°
4x=52
x=13
ATQ,
5x+4+∠A= 180°(adjacent angles)
69+∠A=180°
∠A= 111°
and ∠A=∠C=111°
and ∠B=180°-111
=69° = ∠D
So ∠A=111°,∠B=69°,∠C=111°,∠D=69°
______________________________________________THANKS :) _____
JOEL71:
I got 13,167,13,167
Answered by
13
Hi friend !!
We know that opposite angles of a parallelogram are equal.
Hence ,
(5x-4)° = (x+48)°
5 x - x = 48 + 4
4 x = 52
x = 52/4
x = 13
Therefore , the angles are :
5x - 4
= 5 × 13- 4 = 61°
We know that opposite angles of a parallelogram are equal.
Hence ,
(5x-4)° = (x+48)°
5 x - x = 48 + 4
4 x = 52
x = 52/4
x = 13
Therefore , the angles are :
5x - 4
= 5 × 13- 4 = 61°
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