Question

the opposite angles of a parallelogram
$(3x - 2) raise to zero \: and \: (2x +10)raise \: to \: zero$
Find the measure of each angle

Answer 1

Angles given are

$(3x - 2) {}^{0} \: \: and \: \: \: (2x + 10) {}^{0}$

Using property opposite angles of parallelogram are equal...

3x - 2 = 2x + 10

3x - 2x = 10 + 12

x = 22

3 x - 2 = 3×22 -2 = 64

2x + 10 = 2×22 +10 = 54

Angles are
$64 {}^{0} \: and \: 54 {}^{0}$