Question

the opposite face of an iron cube in steam(100C) and in ice(0C). Each side of the cube is 2 cm and the thermal conductivity of iron is 0.2 cal / s / cm / C . How much ice will melt in 5 minutes? Latent heat of ice is 80 cal/gm​

Answer 1

Answer:

Explanation:

Answer Text

`300 g`

`150 g`

`75 g`

`450 g`

Answer :

A

Solution :

Let `x` be each side of the cube.

As area `(A)` of each face is `4cm^(2)`

`A = x^(2) = 4 cm^(2) or x=2 cm`

Further, with usual notation,

`(T_(1)-T_(2)) = (100-0) = 100^(@)C`

`(T_(1)` = temperature of steam, `T_(2)` = temperature of melting ice)

`k=0.2 CGS` unit , `t=10 min = 10xx60s = 600s`

As, `Q = (KA(T_(1)-T_(2))t)/(x)`

`Q = (0.2 xx 4 xx 100 xx 600)/(2) = 24,000 cal`

if `m` gram of ice be melting with this heat and `L` be the latent heat of fusion of ice, `Q =mL`

Or, `m=(Q)/(L) = (24000)/(80) (as L = 80cal//g)`

or, `m=300g`.