Question

The opposite of a cubical block of metal 0.20 mitre side are kept in contact with steam and ice . Determine the rate at which the ice melt .
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Answer 1

Answer:

The heat transfer equation is given by:

Q

˙

=KA

l

ΔT

The heat flows for 10min, i.e. heat absorbed by ice = 600

Q

˙

(600 seconds = 10 minutes)

This heat flow is equal to the latent heat of fusion times the mass of melted ice.

600

Q

˙

=600KA

l

ΔT

=m

melted

L

fusion

i.e.

m

melted

=600KA

L

fusion

l

ΔT

=600×0.2×(4)

2×80

100

=300g