The orbital angular momentum of an electron in 25 orbital is :
Answers
Explanation:
Orbital angular momentum depends upon the Azimuthal qualtam number (l). For a 3p electron l = 1
Now the formula for orbital angular momentum is, -> squarerootof[l∗(l+1)] * h/2π .
For a p subshell azimuthal quantum number l =1.
Now you can calculate. It will be 2*h/2π.
So basically orbital angular momentum quantum no. of any orbital is represented by symbol (l).
And we all commonly use the term azimuthal quantum number.
The, l of p orbitals is 1,
Therefore l of 3p is also (1).
And magnitude of orbital angular momentum is h/2Π ×√l(l+1)
Ans = h/2Π×√1(1+1)
=h/2Π× √2
You can calculate further.
Angular momentum is denoted by
→
L
.
Definition :-
The instantaneous angular momentum
→
L
of the particle relative to the origin
O
is defined as the cross product of the particle’s instantaneous position vector
→
r
and its instantaneous linear momentum
→
p
→
L
=
→
r
×
→
p
For a rigid body having fixed axis rotation , the angular momentum is given as
→
L
=
I
→
ω
; where
I
is the Moment of Inertia of the body about the axis of rotation.
The net torque
→
τ
acting on a body is give as the rate of change of Angular Momentum.
∴
∑
→
τ
=
d
→
L
d
t
Answer: It will be 2*h/2π.
Explanation:
Orbital angular momentum depends upon the Azimuthal qualtam number (l). For a 3p electron l = 1
Now the formula for orbital angular momentum is, -> squarerootof[l∗(l+1)] * h/2π .
For a p subshell azimuthal quantum number l =1.
Now you can calculate. It will be 2*h/2π.
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