Question

The orbital angular momentum of an electron in 4s-orbital is

Answer 1

Explanation:

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Answer 2

Answer:

0

Explanation:

Orbital angular momentum

$= \sqrt{l(l + 1)} \times \frac{h}{2\pi} \\ = \sqrt{0(0 + 1)} \times \frac{6.626 \times {10}^{ - 34} }{2 \times \frac{22}{7} } \\ = 0$

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