Chemistry, asked by xdash, 3 months ago

The orbital angular momentum of an electron is ✓3h/π

Which of the following should not be the permissible value of orbit angular momentum of this electron revolving in Bohr orbit?​

Answers

Answered by sukhdeepkaur60
0

Answer:

Solution :

Orbital angular momentum =

l(1+l)

h

(l = azimulthal quantum no)

Given O.A.M=

3

π

h

L(1+1)

×

h

=

3

π

h

4

L(1+1)

=3⇒l(1+1)=12

We have : l

2

+l−12=0⇒(l+2)(l−3)=0

Possible values of L=−4,3.(−4 not allowed as L<0)

∴L=3

For L=3, Possible values of n=4,5,6

Thus, possible angular momentum =

4h

,

5h

,

6h

,

7h

,...

From the all available Options,

π

3h

is correct answer which is equivalent to

bh

(at n=6 )

hope it helped u out..


xdash: nah wrong answer
sukhdeepkaur60: no it is write, if it is wrong can u pls tell me the reason for it
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