The orbital angular momentum of an electron is ✓3h/π
Which of the following should not be the permissible value of orbit angular momentum of this electron revolving in Bohr orbit?
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Answer:
Solution :
Orbital angular momentum =
l(1+l)
2π
h
(l = azimulthal quantum no)
Given O.A.M=
3
π
h
∴
L(1+1)
×
2π
h
=
3
π
h
⇒
4
L(1+1)
=3⇒l(1+1)=12
We have : l
2
+l−12=0⇒(l+2)(l−3)=0
Possible values of L=−4,3.(−4 not allowed as L<0)
∴L=3
For L=3, Possible values of n=4,5,6
Thus, possible angular momentum =
2π
4h
,
2π
5h
,
2π
6h
,
2π
7h
,...
From the all available Options,
π
3h
is correct answer which is equivalent to
2π
bh
(at n=6 )
hope it helped u out..
xdash:
nah wrong answer
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