Question

The orbital angular momentum of an electron is ✓3h/π

Which of the following should not be the permissible value of orbit angular momentum of this electron revolving in Bohr orbit?​

Answer 1

Answer:

Solution :

Orbital angular momentum =

l(1+l)

2π

h

(l = azimulthal quantum no)

Given O.A.M=

3

π

h

∴

L(1+1)

×

2π

h

=

3

π

h

⇒

4

L(1+1)

=3⇒l(1+1)=12

We have : l

2

+l−12=0⇒(l+2)(l−3)=0

Possible values of L=−4,3.(−4 not allowed as L<0)

∴L=3

For L=3, Possible values of n=4,5,6

Thus, possible angular momentum =

2π

4h

,

2π

5h

,

2π

6h

,

2π

7h

,...

From the all available Options,

π

3h

is correct answer which is equivalent to

2π

bh

(at n=6 )

hope it helped u out..