Chemistry, asked by rabdeepkaur, 3 months ago

the orbital angular momentum of an electron present in 3p orbital is
1)√2h, 2)zero, 3)√6h, 4) 2√2h

Answers

Answered by deepikaarya
0

Explanation:

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Answered by Decapod
1

Answer: (3) √6 ħ

Explanation:

Orbital angular momentum of an e- given in an orbital is given by:

ħ[l(l + 1)] = h/2π[l(l + 1)]

Value of l in 3p orbital = 1

Therefore, orbital ang momentum = ħ√(2 × 3) = √6 ħ

More:

The p-orbital, alike other orbitals, have some shapes. They are px, py, and pz. px lies on X axis, py on Y axis and pz on Z axis. They shape of the s-orbital is circular and d-orbital is dūmbbell shaped. d-orbital shape includes dxy, dxz, dyz, dx²-y² and dz². f-orbital has a complex leaf like shape.

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