Question

The orbital angular momentum of an electron which is present in 'p' orbital is

Answer 1

Orbital angular momentum of an electron in particular orbital is given by under root l(l+1) h/2pi where `l` is azimuthal quantum no. For p orbital l=1 so orbital angular momentum is \/2 h/2pi. h/2pi comes from the wave nature consideration of electron. Waves associated with electrons so circumference of a circle must be integral multiple of wavelength. So only these orbits are permissible otherwise wave will intersect and amplitude become zero that means no possibility of electron to be found in that orbit.