Question

The orbital angular momentum of ap-electron is given as:

1) √6*h/12.

2) h/ √2π.

3)√3*h/ √2π.

4)√3/2*h/π.

Answer 1

Answer:(2)

Explanation:[l(l+1)] ^1/2 h/2π = orbital angular momentum=

√2h/2π (for a p - orbital ,l=1