The orbital angular momentum of f orbital electron....
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Here is your answer !!!
the orbital angular momentum of f orbital is given by => h / 2π ( √l ( l + 1 )
so we have f so l will be => 3
so your answer will be =>
h / 2π (√ 3( 3+1)
or
h / 2π ( √ 12 )
where h is Plank's constant
hope it help you !!
thanks !!
the orbital angular momentum of f orbital is given by => h / 2π ( √l ( l + 1 )
so we have f so l will be => 3
so your answer will be =>
h / 2π (√ 3( 3+1)
or
h / 2π ( √ 12 )
where h is Plank's constant
hope it help you !!
thanks !!
inriyasharma:
Thanks but ur ans does not match the options
Answered by
0
See we have a formula i.e√l(l+1) h/2π where l is azuimuthal quantum no. So the value of l for f orbital is 3 the answer is √12 h/2π
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