Chemistry, asked by ribikanaik8402, 1 year ago

The orbital angular momentum of f orbital electron is equal to
(1)√3h/π
(2)3h/π
(3)√2h/π
(4)√3/2h/π

Answers

Answered by RomeliaThurston
33

Answer: The correct option is 1.

Explanation:

Formula used for the calculation of the total orbital angular momentum for an electron is :

L=\sqrt{l(l+1)}\frac{h}{2\pi }

Value of l for the electron present in f-sub shell is 3

Putting the value of l = 3 in above equation, we get

L=\sqrt{3(3+1)}\frac{h}{2\pi }

L=\frac{\sqrt{3}h}{\pi }

The orbital angular momentum of an electron present in f-sub shell is \frac{\sqrt{3}h}{\pi }

Hence, the correct option is 1.

Answered by Kritichopra
2

Answer:

the perfect and correct answer to this easy question is 1) pary

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