Question

the orbital velocity of satellite very near to surface of a v. Its orbital velocity at an altitude 7 times the radius of the earth

Answer 1

we know that for a satellite moving in orbit

gravitational force = centripetal force

so,

GMm / r2 = mv2 / r

Here r is the radius of the earth as the satellite is moving very close to it. Now,

by rearranging we get

v2 = GM/r

so, the orbital velocity will be

v = √(GM/r)

or as g = GM/r2

v = √(gr)

Answer 2

Refer the attachment above ..

Hope it Helps !!