Question

The orbital wave function y for an electron in an atom is a mathematical function and as such does not convey any physical sense. However, y 2 makes a physical sense. Its value at a particular point in an atom gives the probability density of the electron at that point. The region in which the probability density function, i.e., y 2 reduces to zero is called nodal surface. There are two types of nodal surface (i) Radial node (ii) Angular node. The shape of an orbital can be obtained with the help of probability density. The shape of an orbital is defined as a surface of constant probability density that encloses some large fraction (say 90%) of the probability of finding the electron. 22. Which of the following statements regarding 2s orbital is INCORRECT ? (A) It is spherically symmetrical (B) It possess one nodal surface (C) it lies along X-axis (D) In it, the density is maximum at the nucleus which falls off to zero at a certain distance, further increases to a maximum and then falls off with the increases in distance from the nucleus. 23. Which of the following radial distribution curves is not correctly plotted ?​

Answer 1

Answer:

Correct option is

B.Electron density in XY plane of 3d z 2orbital is zero.

C.2s orbital has only one spherical node.

Orbital is formed where the probability of finding an electron is maximum. Hence in first option, as those are orbitals electron density will not be zero. In the 3rd option for a spherical node, we have to use (n−l−1). Here n=2;l=0; we get spherical node as 1. In the 4th option, we get XY as a nodal plane because in the z orbital, a probability of finding an electron is maximum. Hence we could not find an electron in XY plane.

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Answer 2

Out of all given options, the Correct option is

(B) It possesses one nodal surface

because Electron density in the XY plane of 3d z 2orbital is zero.